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(Arpatubes)   A simple math puzzle. See if you can get your name on the list   ( puzzle.arpatubes.net) divider line
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55541 clicks; posted to Main » on 29 Nov 2007 at 12:48 AM (9 years ago)   |   Favorite    |   share:  Share on Twitter share via Email Share on Facebook   more»



534 Comments     (+0 »)
 


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2007-11-27 09:05:01 AM  
i managed to get it in a single go
 
2007-11-27 09:07:09 AM  
tedium is not the same thing as a puzzle.
 
2007-11-27 09:08:14 AM  
I feel dumb. 4 tries.
 
2007-11-27 09:11:30 AM  
I was told there wouldn't be any math on TF.
 
2007-11-27 09:12:35 AM  
I didn't know story problems were puzzles.

But it gave me something to do for a minute.
 
2007-11-27 09:21:07 AM  
First try. The answer is 459
 
aba
2007-11-27 09:22:51 AM  
Maybe I'm missing something....

7 children = 14 legs

7 rucksacks with 14 cats each = 392 legs

14 + 392 = 406 legs
 
2007-11-27 09:23:22 AM  
www.achievement.org

" As I was going to St Ives
I met a man with seven wives

And every wife had seven sacks
And every sack had seven cats
And every cat had seven kittens

Kittens, cats, sacks, wives
How many were going to St Ives? "
 
2007-11-27 09:23:57 AM  
read closer, you have not understood the problem
 
2007-11-27 09:35:02 AM  
every sack had seven cats...

kittens ain't there

yea I ruined it...

lame
 
2007-11-27 09:35:04 AM  
aba: Maybe I'm missing something....

7 children = 14 legs

7 rucksacks with 14 cats each = 392 legs

14 + 392 = 406 legs


Read again and check the rucksack count.

/got it on my first try
//suck at math
///self-esteem rising
 
aba
2007-11-27 09:36:48 AM  
Yeah, I hate math
 
2007-11-27 09:40:03 AM  
Not so much math as simple reading comprehension.
 
2007-11-27 09:40:12 AM  
Wait! Who the f*ck uses "rucksacks"?

I refuse to answer this on the grounds its a dumb word.
 
2007-11-27 09:42:23 AM  
Took me three tries (I finally broke down and used Excel). And yeah, it's more about reading comprehension.
 
2007-11-27 09:42:42 AM  
Let's see...

7*4 = 28 (Number of small cat legs per big cat per rustsack per child)
28*7 = 196 (Number of cat legs per rustsack per child)
196*7 = 1372 (Number of legs in all rustsacks per child)
1372*7 = 9604 (Number of all legs in all rustsacks)
9604+14 = 9618 (Number of legs total)

I still don't see what I'm missing...
 
2007-11-27 09:43:39 AM  
jasonmicron: I still don't see what I'm missing...

Your big cats don't have legs?
 
2007-11-27 09:48:22 AM  
It's too early for this shiat.
 
2007-11-27 09:59:59 AM  
i hope the children put the rucksacks over their heads...
 
2007-11-27 10:03:38 AM  
The wording of the problem unfortunately leaves the possibility of multiple correct answers.
 
2007-11-27 10:14:23 AM  
1st try...glad that engineering degree is good for something.
 
2007-11-27 10:15:13 AM  
SRLN: The wording of the problem unfortunately leaves the possibility of multiple correct answers.

Nope. Read it carefully.
 
2007-11-27 10:17:11 AM  
PurplePimpSaber: 1st try...glad that engineering degree is good for something.

Hell, I got it on the first try and my degree is in communications.
 
2007-11-27 10:26:02 AM  
was it necessary for you to post the answer?
 
2007-11-27 10:30:46 AM  
PurplePimpSaber: SRLN: The wording of the problem unfortunately leaves the possibility of multiple correct answers.

Nope. Read it carefully.


it actually does leave it open for multiple answers. think of it this way: 7 children are in school. each (or "every") child has 7 classes. how many classes are there? the way this and the "puzzle" on the site are worded leave a huge number of possible correct answers (i'm sure someone could figure the actual number of correct answers out with permeutations and such). the nutsacks don't need to be exclusive to each child, and the kittens don't have to be exclusive to each cat.

/second try due to an error that i can't even reproduce
 
2007-11-27 10:32:47 AM  
ajt167: PurplePimpSaber: SRLN: The wording of the problem unfortunately leaves the possibility of multiple correct answers.

Nope. Read it carefully.

it actually does leave it open for multiple answers. think of it this way: 7 children are in school. each (or "every") child has 7 classes. how many classes are there? the way this and the "puzzle" on the site are worded leave a huge number of possible correct answers (i'm sure someone could figure the actual number of correct answers out with permeutations and such). the nutsacks don't need to be exclusive to each child, and the kittens don't have to be exclusive to each cat.

/second try due to an error that i can't even reproduce


a cat cant have 7 of the same kitten. and you cant have 7 of the same rucksack.
 
2007-11-27 10:32:47 AM  
ajt167: the nutsacks don't need to be exclusive to each child,

Only the male children have nutsacks, I assume.
 
2007-11-27 10:33:54 AM  
PurplePimpSaber: SRLN: The wording of the problem unfortunately leaves the possibility of multiple correct answers.

Nope. Read it carefully.



I first read the problem as a riddle:

FACTS:
There is a bus with 7 children inside of it (It is established that the children are in the bus)
There is no driver
Each child has 7 rucksacks (Do the children have the rucksacks with them on the bus?)
In each rucksack are 7 big cats
Every big cat has 7 small cats (Are the small cats inside the rucksacks like the big cats or are they not on the bus?)
Every child has two legs
Every cat has 4 legs

QUESTION:
How many legs are in the Bus?

My first answer was 14.
My second answer was the one they were looking for.
 
2007-11-27 10:36:07 AM  
SRLN: The wording of the problem unfortunately leaves the possibility of multiple correct answers.

It's badly worded, but not a trick question.

Unlike the St. Ives version of this puzzle, which changes the words to trick the reader, here the reader isn't supposed to be tricked although this problem misuses the word has. In one case, "has" means carry with them, and the other case, "has" could mean "gave birth to" or "fathered" (depending on the big cats' genders, or could mean "has with them". It's used yet again to mean "attached to them" (presumably, but not actually important for the math) in the case of their own legs.

However, at the end of the day, no tricks: all kids, rucksacks, cats, and more cats, are in the bus.

The problem is to do the math in sets or steps, rather than add it all up. For each step, multiply until you're talking about something with legs, then count those legs. Start over again multiplying till you reach the next thing with legs, count those. Start over again till you reach the last thing with legs, count those. Total, and done.

// not submitter
 
2007-11-27 10:48:39 AM  
SRLN: My first answer was 14.


Yeah, I popped in a couple right off the bat because I thought it was going to be a stupid riddle or something. So I tried 14, and 0 just for the heck of it...
 
2007-11-27 10:48:45 AM  
the_rev: ##### cat legs + ## child legs = ##,### total legs

Spoiler. Giving the answer is not really a hint....

Also, that approach was sort of inside out. A straightforward approach is to just work in the order of the problem, totaling up legs as you run into them:

There is a bus with 7 children inside of it = children * 2 = _x_ legs
There is no driver = 0 legs
Each child has 7 rucksacks = 0 legs
In each rucksack are 7 big cats = children * rucksacks * big cats * 4 = _y_ legs
Every big cat has 7 small cats = children * rucksacks * big cats * small cats * 4 = _z_ legs

Total legs = x + y + z
 
2007-11-27 10:51:55 AM  
SPOILER

its a progression of powers of seven

legs == 7^1 *2 + 7^2 *0 + 7^3 *4 + 7^4 *4
 
2007-11-27 11:01:07 AM  
Sorry, all... everyone else was showing their work.
 
2007-11-27 11:04:05 AM  
first try.
 
2007-11-27 11:19:55 AM  
sollucky: first try.


I would imagine that it's pretty easy now...
 
2007-11-27 04:21:39 PM  
First try. I worked it out by how many legs per bag*number of bags+kids legs.
 
2007-11-28 08:51:43 AM  
First I put 10, and I was wrong
Then I put 9, and although I was closer, I was still very far from the answer.
Then I put 90 and I got it.

/This puzzle is just about as dumb as the one in the link that took me 3 tries because I didn't read it carefully.
 
2007-11-29 12:09:24 AM  
Blah. I can't believe how much I sucked at that. I forgot a seven for some reason.
 
2007-11-29 12:25:16 AM  
Dammit. 2 tries.
 
2007-11-29 12:32:42 AM  
Easy.

Spoiler (select to read): (4x7^4)+(4x7^3)+14

Why is that so difficult?
 
2007-11-29 12:39:46 AM  
Bah, Four tries but in my defense I'm extremely drunk.

This isn't a math problem, it's a reading problem. In real life, however, it's one in the same so good show.

A hint for the newbies: "Each" plays an insanely important part in this question.

In retrospect, this is well more a language problem than a math one. The evil English majors are attempting to pretend a poorly worded math problem actually involves math - but the trickery here involves nothing more than language.

If I wasn't drunk and tired I'd set up a web site about the conspiracy. Hopefully someone will take the initiative. Please involve Bush and 9/11.
 
2007-11-29 12:50:25 AM  
Subby lost me at the word "math."
 
2007-11-29 12:55:26 AM  
content.answers.com

/approves
 
2007-11-29 12:55:34 AM  
fark'd?
 
2007-11-29 12:56:04 AM  
the answer is 42
 
2007-11-29 12:56:33 AM  
kids = 7
big_cats = 7**3
small_cats = 7**4
cats = 7**3 + 7**4 = 2744

cat_legs = cats * 4 = 10976
kid_legs = kids * 2 = 14

total_legs = cat_legs + kid_legs = 10990

/that was really easy
 
2007-11-29 12:58:48 AM  
Okay, maybe not totally farked. But nearly, anyway.

Also really really easy.

/math major
 
2007-11-29 12:58:58 AM  
CaptainJuan: fark'd?

fark'd.
 
2007-11-29 12:59:13 AM  
farked. does that mean i fail?
 
2007-11-29 12:59:56 AM  
King Something: /approves

now why can't this be an あずまんが大王 thread instead of silly math problems?!
 
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